What is the mass of 3.01 × 10²³ molecules of glucose (C₆H₁₂O₆, molar mass = 180 g/mol)?
Q1. What is the mass of 3.01 × 10²³ molecules of glucose (C₆H₁₂O₆, molar mass = 180 g/mol)?
Answer: 90 g
Explanation: 3.01×10²³ / 6.02×10²³ = 0.5 mol → 0.5 × 180 = 90 g. Option C divides by 2 incorrectly.