MDCAT Chemistry MCQ #2800

What is the mass of 0.2 moles of CaCO₃ (molar mass = 100 g/mol)?

MDCAT Chemistry MCQ #2800

  1. Question 1

    Q1. What is the mass of 0.2 moles of CaCO₃ (molar mass = 100 g/mol)?

    • A) 20 g
    • B) 40 g
    • C) 60 g
    • D) 100 g

    Answer: 20 g

    Explanation: 0.2 × 100 = 20 g. Option B triples the value.