MDCAT Chemistry MCQ #2806

What volume of 0.500 M HCl is required to neutralize 25.0 mL of 0.200 M Ca(OH)₂?

MDCAT Chemistry MCQ #2806

  1. Question 1

    Q1. What volume of 0.500 M HCl is required to neutralize 25.0 mL of 0.200 M Ca(OH)₂?

    • A) 10.0 mL
    • B) 20.0 mL
    • C) 40.0 mL
    • D) 5.0 mL

    Answer: 40.0 mL

    Explanation: 2×0.200×0.025 /0.500 = 0.04 L = 40.0 mL. B ignores 2:1 molar ratio.