MDCAT Chemistry MCQ #2811

What is the mass of Mg in 6.0 g of Mg₃(PO₄)₂? (Mg = 24.31 g/mol, P = 30.97 g/mol, O = 16.00 g/mol)

MDCAT Chemistry MCQ #2811

  1. Question 1

    Q1. What is the mass of Mg in 6.0 g of Mg₃(PO₄)₂? (Mg = 24.31 g/mol, P = 30.97 g/mol, O = 16.00 g/mol)

    • A) 1.5 g
    • B) 2.2 g
    • C) 2.7 g
    • D) 3.0 g

    Answer: 2.7 g

    Explanation: Mass Mg = (3×24.31/262.86)×6.0 = 2.7 g. A calculates only 1 Mg atom.