MDCAT Chemistry MCQ #2827

If 0.5 mol of O2 occupies 11.2 L at STP, what pressure is exerted? (R = 0.0821 L·atm/mol·K)

MDCAT Chemistry MCQ #2827

  1. Question 1

    Q1. If 0.5 mol of O2 occupies 11.2 L at STP, what pressure is exerted? (R = 0.0821 L·atm/mol·K)

    • A) 1.0 atm
    • B) 2.0 atm
    • C) 0.5 atm
    • D) 4.0 atm

    Answer: 1.0 atm

    Explanation: PV = nRT → P = (0.5 × 0.0821 × 273)/11.2 ≈ 1 atm. Option B assumes 22.4 L instead of 11.2 L.