MDCAT Chemistry MCQ #3942

In the reforming process, n-octane is converted to 2,2,4-trimethylpentane. What is the change in the number of primary carbons between these two isomers?

MDCAT Chemistry MCQ #3942

  1. Question 1

    Q1. In the reforming process, n-octane is converted to 2,2,4-trimethylpentane. What is the change in the number of primary carbons between these two isomers?

    • A) 1
    • B) 3
    • C) 5
    • D) 2

    Answer: 3

    Explanation: Iso-octane has five primary carbons while n-octane has two. 1 is wrong, misidentifying the number of terminal methyl groups.