If the bond angle in a specific hydrocarbon is measured at 109.5 degrees, what is the percentage of p-character in the hybrid orbitals of the central carbon?
Q1. If the bond angle in a specific hydrocarbon is measured at 109.5 degrees, what is the percentage of p-character in the hybrid orbitals of the central carbon?
Answer: 75%
Explanation: sp3 hybrids consist of 25% s and 75% p character. 25% is wrong because it refers to the s-character instead.