MDCAT Chemistry MCQ #3978

Based on the percentage of s-character, how does the bond length of an sp hybridized carbon contrast with sp2 and sp3 carbons?

MDCAT Chemistry MCQ #3978

  1. Question 1

    Q1. Based on the percentage of s-character, how does the bond length of an sp hybridized carbon contrast with sp2 and sp3 carbons?

    • A) sp3 hybrid orbitals are the shortest
    • B) sp2 hybrid orbitals are shorter than sp orbitals
    • C) All hybrid orbitals have the same length
    • D) sp hybrid orbitals are the shortest

    Answer: sp hybrid orbitals are the shortest

    Explanation: The sp orbital has 50% s-character, making it closer to the nucleus and shorter than sp2 (33%) or sp3 (25%) orbitals.