The ratio of rates of diffusion of two gases is 2:1. If the molar mass of the slower gas is 64 g/mol, what is the molar mass of the faster gas?
Q1. The ratio of rates of diffusion of two gases is 2:1. If the molar mass of the slower gas is 64 g/mol, what is the molar mass of the faster gas?
Answer: 16 g/mol
Explanation: Graham's Law: Rate ratio = √(M2/M1). So, M1 = 16 g/mol. Option B is incorrect molar mass.