How many grams of O₂ are required to burn 11.2 g of propane (C₃H₈)?
Q1. How many grams of O₂ are required to burn 11.2 g of propane (C₃H₈)?
Answer: 48.0 g
Explanation: Balanced equation: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. Molar mass ratio gives 48.0 g O₂. Distractor B uses wrong stoichiometry.