MDCAT Chemistry MCQ #481

What mass of benzaldehyde (C7H6O) is required to produce 5.0 g of benzyl alcohol? (Molar masses: C7H6O = 106 g/mol, C7H8O = 108 g/mol)

MDCAT Chemistry MCQ #481

  1. Question 1

    Q1. What mass of benzaldehyde (C7H6O) is required to produce 5.0 g of benzyl alcohol? (Molar masses: C7H6O = 106 g/mol, C7H8O = 108 g/mol)

    • A) 4.9 g
    • B) 5.1 g
    • C) 10.2 g
    • D) 2.4 g

    Answer: 4.9 g

    Explanation: 1:1 molar ratio. 5.0 g / 108 g/mol = 0.0463 mol. 0.0463 mol × 106 g/mol = 4.9 g (B adds excess reagent mistakenly).