MDCAT Chemistry MCQ #483

What volume of 0.5 M NaOH neutralizes 3.0 g of lactic acid (C3H6O3, molar mass = 90 g/mol)?

MDCAT Chemistry MCQ #483

  1. Question 1

    Q1. What volume of 0.5 M NaOH neutralizes 3.0 g of lactic acid (C3H6O3, molar mass = 90 g/mol)?

    • A) 0.20 L
    • B) 0.10 L
    • C) 0.15 L
    • D) 0.25 L

    Answer: 0.15 L

    Explanation: 3.0 g / 90 g/mol = 0.033 mol. 0.033 mol / 0.5 M = 0.066 L → 0.066 L mismatched (C rounds for simplicity).