What is the molarity of a solution containing 2.2 g of acetone in 500 mL of solvent? (Molar mass = 58 g/mol)
Q1. What is the molarity of a solution containing 2.2 g of acetone in 500 mL of solvent? (Molar mass = 58 g/mol)
Answer: 0.076 M
Explanation: 2.2 g / 58 g/mol = 0.038 mol. 0.038 mol / 0.5 L = 0.076 M (B doubles for wrong volume).