What volume of O2 (at STP) is required to oxidize 4.4 g of acetaldehyde to acetic acid?
Q1. What volume of O2 (at STP) is required to oxidize 4.4 g of acetaldehyde to acetic acid?
Answer: 1.1 L
Explanation: 1 mole of aldehyde requires 0.5 moles O2. 4.4 g / 44 g/mol = 0.1 mol. 0.1 × 0.5 × 22.4 L = 1.1 L (A ignores stoichiometry).