For a certain reaction, the rate constant at 300 K is 2.5 × 10^(-3) s^(-1) and at 310 K is 5.0 × 10^(-3) s^(-1). What is the activation energy?
Q1. For a certain reaction, the rate constant at 300 K is 2.5 × 10^(-3) s^(-1) and at 310 K is 5.0 × 10^(-3) s^(-1). What is the activation energy?
Answer: 53.6 kJ/mol
Explanation: Using Arrhenius equation, Ea = RT1T2 ln(k2/k1)/(T2-T1) = 53.6 kJ/mol.