The activation energy for a reaction is 50 kJ/mol. If the rate constant at 300 K is 2 × 10^(-3) s^(-1), what is the rate constant at 320 K?
Q1. The activation energy for a reaction is 50 kJ/mol. If the rate constant at 300 K is 2 × 10^(-3) s^(-1), what is the rate constant at 320 K?
Answer: 8.34 × 10^(-3) s^(-1)
Explanation: Using Arrhenius equation, k2 = k1 exp(Ea/R(1/T1 - 1/T2)) = 8.34 × 10^(-3) s^(-1).