MDCAT Chemistry MCQ #5148

A catalyst lowers the activation energy from 100 kJ/mol to 80 kJ/mol. By what factor does the rate constant increase at 300 K?

MDCAT Chemistry MCQ #5148

  1. Question 1

    Q1. A catalyst lowers the activation energy from 100 kJ/mol to 80 kJ/mol. By what factor does the rate constant increase at 300 K?

    • A) 2.35 × 10^3
    • B) 1.65 × 10^2
    • C) 55.46
    • D) 1.04 × 10^4

    Answer: 55.46

    Explanation: Using Arrhenius equation, k2/k1 = exp((Ea1 - Ea2)/RT) = 55.46.