MDCAT Chemistry MCQ #5151

For a certain reaction, the rate constant doubles when the temperature increases from 298 K to 308 K. What is the activation energy?

MDCAT Chemistry MCQ #5151

  1. Question 1

    Q1. For a certain reaction, the rate constant doubles when the temperature increases from 298 K to 308 K. What is the activation energy?

    • A) 52.9 kJ/mol
    • B) 50.3 kJ/mol
    • C) 53.6 kJ/mol
    • D) 51.2 kJ/mol

    Answer: 53.6 kJ/mol

    Explanation: Using Arrhenius equation, Ea = RT1T2 ln(k2/k1)/(T2-T1) = 53.6 kJ/mol.