When sulfur dioxide gas is passed through an acidified solution of potassium dichromate, the orange color changes to green. What is the chemical basis for this change?
Q1. When sulfur dioxide gas is passed through an acidified solution of potassium dichromate, the orange color changes to green. What is the chemical basis for this change?
Answer: It reduces Cr(VI) to green Cr(III) ions
Explanation: Sulfur dioxide is a reducing agent that reduces Cr(VI) in K2Cr2O7 to green Cr(III) in Cr2(SO4)3; KMnO4 would turn colorless, not green.