In a two-step nucleophilic substitution, the first step involves the formation of a reactive intermediate. Which intermediate is most stable and easily formed?
Q1. In a two-step nucleophilic substitution, the first step involves the formation of a reactive intermediate. Which intermediate is most stable and easily formed?
Answer: Tertiary carbocation
Explanation: Tertiary carbocations are stabilized by three electron-donating alkyl groups. Primary carbocations are tempting but are the least stable in SN1 processes.