An unknown alkyl halide forms a yellow precipitate when treated with aqueous silver nitrate and nitric acid. Identify the halide present in the molecule.
Q1. An unknown alkyl halide forms a yellow precipitate when treated with aqueous silver nitrate and nitric acid. Identify the halide present in the molecule.
Answer: Iodide
Explanation: Silver iodide is a distinct yellow precipitate; silver bromide is tempting but forms a pale cream-colored precipitate instead of deep yellow.