When comparing the reactivity of C-X bonds in alkyl halides, why is ethyl iodide more reactive than ethyl fluoride despite being less polar?
Q1. When comparing the reactivity of C-X bonds in alkyl halides, why is ethyl iodide more reactive than ethyl fluoride despite being less polar?
Answer: Bond energy is the primary factor determining reactivity.
Explanation: Bond energy decreases down the halogen group (C-F > C-Cl > C-Br > C-I), making C-I the easiest to break and most reactive.