Dehydrohalogenation of 2-bromobutane with alcoholic KOH yields two alkenes. Which one is the major product according to the PTB syllabus?
Q1. Dehydrohalogenation of 2-bromobutane with alcoholic KOH yields two alkenes. Which one is the major product according to the PTB syllabus?
Answer: 2-Butene is the major product because it is more substituted.
Explanation: Saytzeff's rule states that the more highly substituted alkene (2-butene) is the major product over the less substituted one (1-butene).