In a synthesis lab, a chemist treats 2-bromopropane with alcoholic KOH at a high temperature. What is the major organic product formed?
Q1. In a synthesis lab, a chemist treats 2-bromopropane with alcoholic KOH at a high temperature. What is the major organic product formed?
Answer: Propene
Explanation: Alcoholic KOH promotes elimination (E2) to form alkenes. Aqueous KOH is tempting but it would favor substitution to form propanol.