In a qualitative analysis test, an unknown alkyl halide is treated with aqueous silver nitrate. The formation of which observation confirms it is an iodide?
Q1. In a qualitative analysis test, an unknown alkyl halide is treated with aqueous silver nitrate. The formation of which observation confirms it is an iodide?
Answer: Yellow precipitate
Explanation: Alkyl iodides yield a yellow precipitate with silver nitrate; chlorides give white and bromides give pale yellow. White is the most common error.