Calculate the wavelength of a photon emitted when an electron jumps from n=4 to n=2 in a hydrogen atom. (R=1.097×10^7 m^-1)
Q1. Calculate the wavelength of a photon emitted when an electron jumps from n=4 to n=2 in a hydrogen atom. (R=1.097×10^7 m^-1)
Answer: 486 nm
Explanation: 1/λ = R(1/2^2 - 1/4^2), λ = 486 nm. Option B is for n=4 to n=2 in H-like atom with Z=2.