The ionization energy of He+ is 54.4 eV. What is the ionization energy of Li2+?
Q1. The ionization energy of He+ is 54.4 eV. What is the ionization energy of Li2+?
Answer: 122.4 eV
Explanation: IE ∝ Z^2, Li2+ has Z=3, so IE = 54.4 × (3/2)^2 = 122.4 eV. Option C is for a wrong assumption.