A sinusoidal voltage of peak value 10 V is applied to a diode and a 1 kΩ resistor in series. What is the peak current?
Q1. A sinusoidal voltage of peak value 10 V is applied to a diode and a 1 kΩ resistor in series. What is the peak current?
Answer: 10 mA
Explanation: Peak current = peak voltage / resistance = 10 V / 1 kΩ = 10 mA. Diode is forward biased.