A capacitor of 100 nF is connected in parallel with a resistor of 1 kΩ. What is the impedance at a frequency of 1 kHz?
Q1. A capacitor of 100 nF is connected in parallel with a resistor of 1 kΩ. What is the impedance at a frequency of 1 kHz?
Answer: 796 Ω
Explanation: Xc = 1 / (2πfC) = 1591 Ω. Z = (R * Xc) / sqrt(R^2 + Xc^2) = 796 Ω.