MDCAT Physics MCQ #1522

A charge of 0.5 C is moved from a point of potential 10 V to another point of potential 20 V. The work done is

MDCAT Physics MCQ #1522

  1. Question 1

    Q1. A charge of 0.5 C is moved from a point of potential 10 V to another point of potential 20 V. The work done is

    • A) 5 J
    • B) 10 J
    • C) 15 J
    • D) 20 J

    Answer: 5 J

    Explanation: W = q * ΔV = 0.5 * (20 - 10) = 5 J. Wrong options miscalculate ΔV or q.