MDCAT Physics MCQ #1525

A parallel plate capacitor is charged to 100 V and then isolated. If the plate separation is doubled, the potential difference becomes

MDCAT Physics MCQ #1525

  1. Question 1

    Q1. A parallel plate capacitor is charged to 100 V and then isolated. If the plate separation is doubled, the potential difference becomes

    • A) 50 V
    • B) 100 V
    • C) 200 V
    • D) 400 V

    Answer: 200 V

    Explanation: V = Qd / ε0A, so doubling d doubles V. Wrong options misunderstand capacitor isolation.