MDCAT Physics MCQ #1530

A capacitor is charged to a potential difference of 200 V. If the charge stored is 0.02 C, the capacitance is

MDCAT Physics MCQ #1530

  1. Question 1

    Q1. A capacitor is charged to a potential difference of 200 V. If the charge stored is 0.02 C, the capacitance is

    • A) 100 μF
    • B) 50 μF
    • C) 200 μF
    • D) 400 μF

    Answer: 100 μF

    Explanation: C = Q / V = 0.02 / 200 = 100 μF. Wrong options miscalculate Q or V.