A 2 μC charge moves from 600 V to 200 V. How much work is done?
Question 1
Q1. A 2 μC charge moves from 600 V to 200 V. How much work is done?
Answer: 8×10⁻⁶ J
Explanation: W = qΔV. Option B uses 200 V instead of 400 V difference.