MDCAT Physics MCQ #1829

A water jet of area 0.01 m² strikes a wall at 2 m/s and stops. Calculate the power delivered by the water to the wall.

MDCAT Physics MCQ #1829

  1. Question 1

    Q1. A water jet of area 0.01 m² strikes a wall at 2 m/s and stops. Calculate the power delivered by the water to the wall.

    • A) 20 W
    • B) 40 W
    • C) 80 W
    • D) 160 W

    Answer: 80 W

    Explanation: Power = Force * velocity. For a jet, F = (mass/time) * v = (ρAv) * v = ρAv². Power = ρAv³. Substituting values: 1000 * 0.01 * 8 = 80 W.