To maintain a flow rate of 0.001 m³/s at a speed of 10 m/s, what must be the radius of the pipe?
Q1. To maintain a flow rate of 0.001 m³/s at a speed of 10 m/s, what must be the radius of the pipe?
Answer: 5.6 mm
Explanation: Flow rate Q = Area * v = πr²v. Thus 0.001 = 3.14 * r² * 10. r² ≈ 0.0000318, so r ≈ 0.0056 m or 5.6 mm.