MDCAT Physics MCQ #1862

The surface tension of a liquid is 0.072 N/m. What is the force due to surface tension on a ring of radius 0.02 m?

MDCAT Physics MCQ #1862

  1. Question 1

    Q1. The surface tension of a liquid is 0.072 N/m. What is the force due to surface tension on a ring of radius 0.02 m?

    • A) 0.009 N
    • B) 0.018 N
    • C) 0.036 N
    • D) 0.072 N

    Answer: 0.018 N

    Explanation: F = 2 * 2πrT = 2 * 2π * 0.02 m * 0.072 N/m = 0.018 N; correct application of surface tension formula.