A fluid flows through a horizontal pipe with a constriction. At the constriction, the velocity is 4 m/s and the pressure is 1.5 x 10^5 Pa. If the velocity at the wider section is 2 m/s, what is the pressure?
Q1. A fluid flows through a horizontal pipe with a constriction. At the constriction, the velocity is 4 m/s and the pressure is 1.5 x 10^5 Pa. If the velocity at the wider section is 2 m/s, what is the pressure?
Answer: 1.58 x 10^5 Pa
Explanation: Using Bernoulli's equation: P₁ + ½ρv₁² = P₂ + ½ρv₂²; P₂ = P₁ + ½ρ(v₁² - v₂²) = 1.5 x 10^5 Pa + ½ * 1000 kg/m³ * (4² - 2²) m²/s² = 1.58 x 10^5 Pa; correct application.