A person is standing on a scale in an elevator. If the elevator accelerates downward at 5 m/s^2, what is the normal force exerted on the person?
Q1. A person is standing on a scale in an elevator. If the elevator accelerates downward at 5 m/s^2, what is the normal force exerted on the person?
Answer: 500 N
Explanation: Normal force equals the person's weight minus the force due to acceleration, which equals 600 N - 5 kg * 5 m/s^2.