A 2 kg mass is attached to a spring. If the spring constant is 100 N/m, what is the force exerted on the mass when it is displaced by 0.2 m?
Q1. A 2 kg mass is attached to a spring. If the spring constant is 100 N/m, what is the force exerted on the mass when it is displaced by 0.2 m?
Answer: F = k x x
Explanation: The correct formula is F = k x x, as Hooke's law states that force is directly proportional to displacement.