MDCAT Physics MCQ #2156

A particle is moving in a circular path with a radius of 3 m. If the particle's velocity is 10 m/s, what is the acceleration of the particle?

MDCAT Physics MCQ #2156

  1. Question 1

    Q1. A particle is moving in a circular path with a radius of 3 m. If the particle's velocity is 10 m/s, what is the acceleration of the particle?

    • A) a = v^2 / r
    • B) a = v / r
    • C) a = v^2 / t
    • D) a = v / t

    Answer: a = v^2 / r

    Explanation: The correct formula is a = v^2 / r, as centripetal acceleration is directly proportional to velocity squared and inversely proportional to radius.