The de Broglie wavelength of an electron moving at 10^6 m/s is approximately
Q1. The de Broglie wavelength of an electron moving at 10^6 m/s is approximately
Answer: 0.73 nm
Explanation: λ = h/mv = (6.63×10^-34)/(9.11×10^-31 × 10^6) = 0.73 nm. Other options miscalculate.