MDCAT Physics MCQ #2558

The ionization energy of hydrogen is 13.6 eV. What is the energy required to ionize a hydrogen atom in the n=2 state?

MDCAT Physics MCQ #2558

  1. Question 1

    Q1. The ionization energy of hydrogen is 13.6 eV. What is the energy required to ionize a hydrogen atom in the n=2 state?

    • A) 6.8 eV
    • B) 3.4 eV
    • C) 13.6 eV
    • D) 1.7 eV

    Answer: 3.4 eV

    Explanation: Energy of n=2 state = -13.6/4 = -3.4 eV. Ionization energy from this state is 3.4 eV. Other options misapply formulas.