The energy released in a nuclear fission reaction is 200 MeV. If 1 kg of fuel undergoes fission, what is the total energy released?
Q1. The energy released in a nuclear fission reaction is 200 MeV. If 1 kg of fuel undergoes fission, what is the total energy released?
Answer: 8×10^13 J
Explanation: Number of nuclei in 1 kg = Avogadro's number × 1000/235 (approx.). Energy = 200 MeV × this number ≈ 8×10^13 J. Other options miscalculate.