MDCAT Physics MCQ #2575

In nuclear fission, 0.1% mass is converted to energy. What formula calculates energy released?

MDCAT Physics MCQ #2575

  1. Question 1

    Q1. In nuclear fission, 0.1% mass is converted to energy. What formula calculates energy released?

    • A) E = Δmc²
    • B) E = mc²/2
    • C) E = 0.1m × c
    • D) E = mc² × 0.1%

    Answer: E = Δmc²

    Explanation: Einstein's formula directly relates mass loss to energy. Option D ignores c².