MDCAT Physics MCQ #2590

Energy released in fusion of ²¹H + ³¹H → ⁴²He + n is... (Q = 17.6 MeV)

MDCAT Physics MCQ #2590

  1. Question 1

    Q1. Energy released in fusion of ²¹H + ³¹H → ⁴²He + n is... (Q = 17.6 MeV)

    • A) 17.6 MeV
    • B) 35.2 MeV
    • C) 8.8 MeV
    • D) 2.2 MeV

    Answer: 17.6 MeV

    Explanation: Q-value is directly given as 17.6 MeV. Option B doubles the correct value.