The frequency of the photon emitted when an electron jumps from n=4 to n=3 in hydrogen atom is given by
Q1. The frequency of the photon emitted when an electron jumps from n=4 to n=3 in hydrogen atom is given by
Answer: f = (E4 - E3)/h
Explanation: Frequency is given by f = (E4 - E3)/h; option B is incorrect because energy difference should be positive.