The activity of a radioactive sample is 5000 Bq. If the decay constant is 0.02 min^-1, how many nuclei are present?
Q1. The activity of a radioactive sample is 5000 Bq. If the decay constant is 0.02 min^-1, how many nuclei are present?
Answer: 250000
Explanation: Activity = λN, so N = Activity / λ. Converting λ to s^-1, we get N = 5000 / (0.02/60) = 250000. Option 'B' uses λ in min^-1 directly.