If a neutron moderator slows neutrons from 2 MeV to 0.025 eV, what is the ratio of their kinetic energies before and after?
Q1. If a neutron moderator slows neutrons from 2 MeV to 0.025 eV, what is the ratio of their kinetic energies before and after?
Answer: 80000:1
Explanation: Energy ratio = 2 × 10⁶ eV / 0.025 eV = 80,000. Option C ignores the correct unit conversion.