MDCAT Physics MCQ #3388

A refrigerator's coefficient of performance is 5. How much heat is removed from the cold body if 1 kJ of work is done?

MDCAT Physics MCQ #3388

  1. Question 1

    Q1. A refrigerator's coefficient of performance is 5. How much heat is removed from the cold body if 1 kJ of work is done?

    • A) 2 kJ
    • B) 5 kJ
    • C) 10 kJ
    • D) 0.2 kJ

    Answer: 5 kJ

    Explanation: COP = Q_c / W, so Q_c = COP * W = 5 * 1 kJ = 5 kJ. Other options miscalculate COP or its implications.