The efficiency of a Carnot engine is 0.5. If the temperature of the hot reservoir is 500 K, what is the temperature of the cold reservoir?
Q1. The efficiency of a Carnot engine is 0.5. If the temperature of the hot reservoir is 500 K, what is the temperature of the cold reservoir?
Answer: 250 K
Explanation: η = 1 - (T_c / T_h), so T_c = T_h * (1 - η) = 500 K * (1 - 0.5) = 250 K. Other options miscalculate or misunderstand Carnot efficiency.